A Yankee bet is a type of system bet that combines 4 selections from different events and generates 11 individual bets with a single wager. If you're wondering how many bets a Yankee system includes, they are organized as follows:
- 6 doubles (combinations of 2 selections)
- 4 trebles (combinations of 3 selections)
- 1 fourfold (all 4 selections together)
How many selections do I need to get right to win a Yankee bet?
In a Yankee bet, you need to get at least 2 of the 4 selections right to make a profit. If you get only 1 selection right, none of the 11 individual bets win, and you lose the amount wagered.
The more selections you get right, the greater your winnings will be, because more combinations within the system are activated:
- 2 correct: 1 double wins.
- 3 correct: 3 doubles and 1 treble win.
- 4 correct: all 11 bets win (6 doubles, 4 trebles, and 1 fourfold).
How is the amount of a Yankee bet calculated?
The total amount you wager in a Yankee system is divided into 11 equal parts, one for each individual bet. In other words, if you want to know how much a Yankee bet costs, multiply the amount of each combination by 11.
Example: if you wager S/5,500 in total, you are wagering S/500 on each of the 11 combinations (S/500 × 11 = S/5,500).
How do I calculate my winnings from a Yankee bet?
To calculate how much you can win from a Yankee bet, multiply the value of each individual bet you got right by the odds corresponding to its selections. Then, add the results of all the individual bets that won. Bets that do not win do not contribute to your winnings.